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WAEC 2019 Mathematics Questions And Answers Now Available

Posted by Examgreat.net Staff on 16th May 2019 4:0PM in

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WAEC 2019 MATHEMATICS ANSWERS


5a)


No of red balls = 3


No of green balls = 5


No of blue balls = x


Prob.(red ball) = no of total outcome/no of possible outcome 


Pr(red) = 3/3+5+x = 1/6


3/8+x = 1/6


6(3) = 1(8+x)


18 = 8 + x


X = 18 - 8 = 10


Therefore the no of blue ball = 10




(5b) 


Probability of picking a green ball 


P(g) = no of green balls/no of possible outcome 


P(g) = 5/3+5+10 = 5/18



=5/18


(6ai)


F ? M1M2/d²


F = KM1M2/d²


Given F = 20N, M1= 25kg, M2 = 10kg and d = 5m


20 = k(25)(10)/5²


250k = 500


k = 500/250 = 2


Expression is 


F = 2M1M2/d²




(6aii) 


Making d subject 


d = ?2M1M2/F


d = ?2 ×7.5×4/30


d = ?60/30 = ?2


d = ?2m or 1.41m




(6b) 


Draw the diagram 


X+X+60+X+80+X+40+X+20 = 540(sum of angles in a Pentagon) 


5x + 200 = 540


5x = 540 - 200


5x = 340


X = 340/5



X = 68


(8a) 


1/3x - 1/4(x+2)>_ 3x -1?


1/3x - 1/4(x+2)>_3x - 4/3


Multiply through by the L. C. M(12), we have 


4x - 3(x + 2)>_36x - 16


4x - 3x - 6 >_ 36x - 16


-6+16 >_36x + 3x - 4x


10 >_ 35x


35x _< 10


X = 10/35


X = 2/7


(8bi) 


Draw the triangle 


|AB|/66 = sin35


|AB| = 66sin35 = 66×0.5736 = 37.8576




Draw the right angled triangle 


|AD|/|AB| = Tan52


|AD| = 37.8576 × Tan52° = 37.8576 × 1.2799 = 48.45m



Height of tower = 48.45m


(11a) 


ar^2=1/4--------(1)


ar^5=1/32------(2)




Divide equations (2) by (1)


ar^3/ar^2=1/32*4/1


r^3=1/8


r=?1/8 (use the cube root sign)


r=1/2




Put r=1/2 into equ (1)


ar^2=1/4


a(1/2)^2=1/4


a/4=1/4


a=1, r=1/2




Tn =ar^n-1 , n=7


ar^7-1=ar^6


=1(1/2)^6



T7=1/64


(4)


Since


Using Pythagoras theorem 


|PR|² = |PQ|² + |QR|²


|PR|² = 3² + 4²


|PR|² = 9 + 16


|PR|² = 25 PR = ?25


|PR| = 5cm


Considering PRS


|PS|² = |PR|²+|SR|²


13² = 5² + |SR|²


169 = 25 + |SR|²


|SR|² = 169 - 25


|SR|² = 144


|SR| = ?144 = 12cm




Hence the area of the quadrilateral = Area of triangle PQR + area of PRS


= 1/2bh + 1/2bh


= 1/2×4×3 + 1/2×12×5



= 6+30 = 36cm


(12a) 


Given : siny = 8/17


Draw the right angle 


From Pythagorean triple, third side is 15


Draw the right angle triangle 


tan y = 8/15


tan y/1+2tany = 8/15/1+2(8/15) = 8/15/1+16/15


tany /1+2tan y = 8/31


(12b) 


Amount shared = #300,000


Otobo's share = #60,000


Ade's share = 5/12 × #(300,000-60,000)


= 5/12 × #240,000


=#100,000


Adeobi's share = #300,000 - (#60,000 + #100,000)


= 300,000 - 160,000


=#140,000


Ratio : Otobo : Ade : Adeola


60,000 : 100,000 : 140,000


60 : 100 : 140


6 : 10 : 14



3 : 5 : 7



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